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Int X 2 4 1 2 3 4 5 6 7 8 Printf D X 2 4
Int X 2 4 1 2 3 4 5 6 7 8 则元素x 1 1 的正确初值是
Int A 2 4 6 8 10
Int X 1.2
执行 Static Int X 2 3 1 2 4 后 X 0 2
Int X 2 Y 4 Z 3 则x Y&&z Y的结果是
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